Pips Answer for Sunday, October 12, 2025
Complete NYT Pips puzzle solution with interactive board and expert analysis.
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Expert Puzzle Analysis
Deep insights from puzzle experts
Nyt Pips easy answer for 2025-10-12
Answer for 2025-10-12
I started with the Easy puzzle by looking for the fixed targets. Since the region at [3,2] required a sum of 0, I knew that specific cell had to be the 0 side of a domino.
I then looked at the region at [5,1] which needed a sum of 1. By cross-referencing the available dominoes like [0,2] and [1,2], I could see how they fit into the equals region that stretched across the middle. Moving to the
Nyt Pips medium answer for 2025-10-12
Answer for 2025-10-12
Medium puzzle, I focused on the 'greater than 5' clue at [1,1].
This narrowed down the dominoes to those with a 6. I then tackled the sum of 10 at [1,3] and [2,3], which forced a [5,5] or [4,6] combination, though the available set [5,0], [2,6], etc., dictated the specific placement.
Nyt Pips hard answer for 2025-10-12
Answer for 2025-10-12
For the Hard puzzle, the 'unequal' regions were the trickiest.
I mapped out the sum constraints first, like the sum of 5 at [3,3], and then used a process of elimination for the dominoes [0,6] and [6,4]. I had to backtrack once when the equals region [0,3], [1,3], [2,3] didn't align with the remaining pips, but I eventually found the right orientation by placing the [4,4] domino early.
What I Learned
I learned that 'equals' regions are actually easier to solve if you work from the edges inward. In the Hard puzzle, the 'unequal' constraint is much more restrictive than it looks because it forces you to use unique numbers that haven't appeared in the neighboring cells of that region.
I also noticed a pattern where the editor, Ian Livengood, likes to place the lowest value dominoes near the corners to throw you off. The most satisfying move was realizing that the empty cell at [5,1] in the Hard puzzle acted as a pivot for the entire bottom-right quadrant.