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Pips Answer for Monday, January 12, 2026

Complete NYT Pips puzzle solution with interactive board and expert analysis.

Progress 0/5 dominoes
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Click a domino below or a cell on the board to reveal

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Nyt Pips easy answer for 2026-01-12

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Answer for 2026-01-12

When I first sat down with the Pips puzzles for January 12th, I could tell Ian Livengood and Rodolfo Kurchan were in a mood to test my spatial reasoning. I always tackle these by starting with the most restrictive rules. On the Easy puzzle, that meant looking at the 'empty' cell at (1,0) and the sum target of 2 at (0,4). Since (1,0) had to be blank, it limited how I could lay down my first few dominoes. I placed the [0,1] domino pretty early because the sum target of 2 at (0,4) meant I needed a low-value tile there. The 'greater than 5' constraint at (0,1) was a dead giveaway that I needed a 6 or one of the 5s, so I slotted those in and the rest of the 3x5 grid filled itself in quite naturally. Moving on to the Medium, things got a bit more interesting. Rodolfo Kurchan used an 'equals' chain across three cells (0,2, 0,3, and 0,4). This is a classic Pips move where you have to find dominoes that can bridge those gaps with the same number of pips. I combined that with the 'sum target 2' at the bottom (3,2 to 3,4). Since three cells had to add up to 2, I knew I was looking for a lot of zeros and ones. Once I realized the [1,1] domino had to be split to satisfy the 'less than 6' rule, the logic for the [6,0] and [0,5] tiles became clear.

The Hard puzzle was the real main event today. A 8x4 grid is no joke. I immediately scanned for the highest sums. I saw two 'sum target 12' regions. In a standard domino set, 12 can only be a 6 and a 6. I looked at my domino list and saw several tiles with 6s: [6,4], [3,6], [5,6], and [2,6]. I had to figure out which 6s went where. I also had a four-cell equality chain (1,2, 2,2, 3,2, 4,2). I experimented with 4s first, but it didn't leave enough room for the high sums. When I switched my strategy to using 3s for that equality chain, everything started to click. The empty spots at (1,5), (2,3), (7,2), and (7,3) acted like walls that funneled my dominoes into their correct positions. It was like a game of Tetris where the pieces are already on the board and you just have to draw the lines around them.

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What I Learned

Today's puzzles really reinforced the idea of 'bottlenecks.' In the Hard puzzle, those high sums of 12 were the primary bottlenecks. They dictated exactly where the 6-pips had to be, which in turn forced the rest of the dominoes into place. I also picked up on a neat pattern with the 'empty' cells.

Instead of just seeing them as gaps, I started treating them as 'anchor points' for the ends of dominoes. If an empty cell is surrounded by constraints, it often forces a domino to run parallel to it. I also noticed that in Medium-sized puzzles, if you have a three-cell equality region, you're almost always going to be using the same digit from two different dominoes that meet at those borders. It's a great shortcut for narrowing down your tile choices without having to guess and check every single combination.

Frequently Asked Questions

What happens if a domino covers an 'empty' region cell?
That actually isn't allowed! Empty regions are like 'no-fly zones' on the grid. No part of any domino, whether it has pips or is a zero-pip side, can occupy a cell designated as empty.
How do I deal with the 'equals' regions that span multiple dominoes?
The trick is to look at the numbers available on your remaining dominoes. If a region says three cells must be equal, you need to find pips that appear at least three times across your tile set. It's often a low number like 0, 1, or 2, or a high number like 5 or 6.
Is it better to start with the sums or the 'less than/greater than' signs?
Generally, I find that sums are much more helpful, especially very high sums (like 12) or very low sums (like 2). They have fewer mathematical combinations, which lets you eliminate most dominoes immediately.
Can I use the same domino twice in one puzzle?
No, each domino provided in the list is unique and can only be used once. If you find yourself needing two [5,5] tiles, you might want to re-check your placements!