Pips Answer for Thursday, February 12, 2026
Complete NYT Pips puzzle solution with interactive board and expert analysis.
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Nyt Pips easy answer for 2026-02-12
Answer for 2026-02-12
Solving the February 12th Pips puzzles was a fun journey through logic and spatial reasoning. I started with Ian Livengood's Easy puzzle to get my gears turning. The first thing I look for are those single-cell 'sum' targets because they act as anchors. Cell [1,0] had to be 4 and cell [2,0] had to be 2. Since cell [1,0] was part of a domino at [[1,0],[0,0]], I knew that domino had to be the [4,0] from my list.
That immediately told me cell [0,0] was 0. From there, the 'equals' constraints created a domino effect—literally. If [0,0] is 0, then [0,1] must be 0 because they are in an equals region. Following that trail allowed me to place the [0,5], [5,3], and [2,3] dominoes until the whole grid snapped into place. Moving on to the
Nyt Pips medium answer for 2026-02-12
Answer for 2026-02-12
Medium puzzle by Rodolfo Kurchan, the difficulty spiked with those sum targets of 8. I scanned my dominoes for pairs that could hit 8. The [6,2] domino was a perfect fit for the [2,0] and [3,0] sum constraint.
The 'empty' cell at [3,3] was a huge clue—it meant that whatever domino crossed into that spot had to have a 0 or blank side. The trickiest part was the chain of equalities in the top row. Once I realized cells [0,1], [0,2], and [0,3] all had to be the same, it narrowed down my remaining dominoes significantly.
Nyt Pips hard answer for 2026-02-12
Answer for 2026-02-12
Finally, the Hard puzzle was a real test of patience. With 15 dominoes and complex chains like the five-cell equality region spanning [1,1] to [3,3], I had to work backwards from the sum-0 constraints.
Sum-0 is a gift in these puzzles because it means both cells must be 0. By locking in the [0,0] and [1,0] dominoes and respecting the 'greater than 4' constraint at the bottom, the logic eventually forced the remaining 6s and 5s into their proper spots.
What I Learned
This set really highlighted how powerful 'equality chains' are. In the Hard puzzle, having five different cells that all must share the same pip value acts like a massive filter. If you find just one domino that doesn't fit that value, you can rule out entire sections of the board.
I also noticed a neat pattern in the Medium puzzle where the sum targets of 8 were placed on opposite sides of the grid, which usually suggests a bit of symmetry in how the dominoes are laid out. Another pro tip I picked up today: always look for the 'empty' or 'sum 0' cells first. They are much easier to satisfy than a sum of 6 or 8, and they usually provide the starting point for the rest of the logic flow.