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Pips Answer for Monday, April 6, 2026

Complete NYT Pips puzzle solution with interactive board and expert analysis.

Progress 0/5 dominoes
6
6
5
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6

Click a domino below or a cell on the board to reveal

Expert Puzzle Analysis

Deep insights from puzzle experts

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Warming Up With A Smooth Morning Puzzle

Nyt Pips easy answer for 2026-04-06

6
6
5
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6

Answer for 2026-04-06

Starting today's easy grid was all about spotting those single-cell regions. Since cell 0,1 had a target sum of 6 and was all by itself, I knew it had to be a 6. I looked at my domino list and saw that 6,0 and 2,6 were available. By looking at the 0,0 and 1,0 sum target of 6, I realized that if I used the 6,0 domino at 0,1 and 0,0, then cell 0,0 becomes a 0. That forced cell 1,0 to be a 6 to meet the sum requirement. It's like a little chain reaction!

Next, I focused on the equals region involving 2,0, 3,0, and 3,1. The only way to satisfy this with the dominoes I had left was to use the 3,3 domino for 3,0 and 3,1. This meant cell 2,0 also had to be a 3. I paired that 3 at 2,0 with the 6 at 1,0 using the 3,6 domino. To wrap things up, the sum of 5 for cells 1,2 and 2,2 fell into place perfectly once I used the 2,6 domino for the bottom right sum target, leaving the 3,0 domino to fill the last empty spot.

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The Great Equals Group Challenge

Nyt Pips medium answer for 2026-04-06

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=
<2
<4

Answer for 2026-04-06

The medium puzzle today was dominated by a massive equals region that stretched across five different cells. It acted as the anchor for the whole board. I noticed that cell 4,1 had to be less than 2 and cell 4,2 had to be less than 4. Because these were paired with cells in the big equals group, I had to find a value that worked for almost half the board. After checking the dominoes, the number 6 stood out. If I set that large equals group to 6, I could use the 6,6 domino in the middle and the 2,6 and 5,6 dominoes on the edges.

Working through the bottom row, I placed the 0,4 domino at 4,1 and 3,1. Since 3,1 is part of a smaller equals region with 2,1, both of those became 4. This then led me to the 4,2 domino for the 2,1 and 2,0 spot. The final check was the first column, where cells 0,0, 1,0, and 2,0 all had to be unequal. With values of 0, 5, and 2 respectively, the whole puzzle clicked together beautifully. It felt great to see that long chain of identical numbers finally resolve!

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Navigating the Giant Grid Maze

Nyt Pips hard answer for 2026-04-06

3
7
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6
6
11
<6
7
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=
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Answer for 2026-04-06

Today's hard puzzle felt like a real brain-buster at first, especially with all those interlocking equals regions on the right side. I started with the most restricted area: the sum 11 at 2,0 and 3,0. In a standard domino set, only 6,5 can make that total, so I placed that domino immediately. Then I looked at the sum 7 targets. By placing the 1,0 domino at the top left, cell 1,1 became a 1, which meant cell 1,2 had to be a 6 to hit that sum of 7. That 6 was part of the 6,6 domino, which filled the 2,2 spot and helped satisfy another sum 7 target at the bottom.

The real breakthrough came when I tackled the equals groups in the middle. I realized that the group containing 1,4, 2,4, and 3,4 had to be 4s to accommodate the 4,4 domino at the bottom. This pushed the 0,4 domino into the 1,5 and 1,4 slot. Once those 4s were in place, the rest of the board started to behave. I had to be careful with the sum 6 at the top right, but using the 2,0 domino for the 1,7 and 2,7 spots allowed the equals group for 2,7 and 3,7 to stay consistent. It was a complex dance of numbers, but every domino found its home!

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Pro Tips for Today's Puzzle

Always start by looking for single-cell regions with a specific target sum, as these are freebies that narrow down your domino choices immediately.

If you see a large region where all cells must be equal, compare it against your remaining dominoes to see which number appears most frequently in pairs. Also, remember to cross off dominoes from your list as you go to avoid trying to use the same one twice!

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What I Learned

Today's puzzles really highlighted how powerful the equals constraint can be when it spans multiple dominoes. In the medium puzzle, that five-cell region was the key to everything. I also learned to pay closer attention to the less than constraints early on, as they often limit the possible values for larger regions they are connected to.

I was surprised by how the hard puzzle used empty regions as buffers. Sometimes the lack of a constraint is just as important as having one, because it gives you the flexibility to place the awkward half of a domino that doesn't fit anywhere else. It is all about finding that balance on the grid.

Frequently Asked Questions

How do you solve NYT Pips puzzles?
To solve NYT Pips, you must place a specific set of dominoes onto a grid so that every cell is covered. You have to follow region constraints like sum (cells add up to a total), equals (all cells have the same value), or unequal (all cells must be different).
What does the empty region mean in Pips?
An empty region in a Pips puzzle means there are no specific mathematical constraints on the cells within that area. You can place any domino values there as long as they don't violate the rules for the dominoes themselves or surrounding regions.
Can I use the same domino twice in one puzzle?
No, you can only use each domino from the provided list exactly once. This is a key strategy for solving the puzzle, as crossing off used dominoes helps you narrow down the remaining possibilities for the rest of the grid.
What is the best strategy for hard Pips puzzles?
The best strategy for hard puzzles is to find the most restrictive regions first, such as high sums (like 11 or 12) or single-cell targets. Once those are placed, look for how equals regions connect different parts of the board to limit the remaining domino choices.
Do dominoes have to be placed horizontally or vertically?
Dominoes in Pips can be placed either horizontally or vertically. Each domino always covers two adjacent cells. Part of the challenge is figuring out the correct orientation to satisfy all the region constraints on the board.